document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37379>Question 37379</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 9^x+4=27^x^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23037 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From 9^(x+4) = 27^(x^2), we turn both the 9 and the 27 into powers of three:<BR>\n" );
document.write( "(3^2)^(x + 4) = (3^3)^(x^2)<BR>\n" );
document.write( "Now use the laws of exponents...<BR>\n" );
document.write( "3^(2x + 8) = 3^(3x^2)<BR>\n" );
document.write( "Now equate the exponents...<BR>\n" );
document.write( "2x + 8 = 3x^2<BR>\n" );
document.write( "and solve this...<BR>\n" );
document.write( "3x^2 - 2x - 8 = 0<BR>\n" );
document.write( "(3x + 4)(x - 2) = 0<BR>\n" );
document.write( "x = -4/3 or x = 2 </SPAN>\n" );
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