document.write( "Question 321756: solve for x: log(x-2) + log(x+2) = 1\r
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Algebra.Com's Answer #230366 by stanbon(75887) ![]() You can put this solution on YOUR website! solve for x: log(x-2) + log(x+2) = 1 \n" ); document.write( "-------- \n" ); document.write( "log[(x-2)(x+2)] = 1 \n" ); document.write( "--- \n" ); document.write( "x^2-4 = 10^1 \n" ); document.write( "--- \n" ); document.write( "x^2-14 = 0 \n" ); document.write( "--- \n" ); document.write( "(x-sqrt(14)(x+sqrt(14) = 0 \n" ); document.write( "Possible solutions: \n" ); document.write( "x = sqrt(14) or x = -sqrt(14) \n" ); document.write( "--- \n" ); document.write( "Check in the original equation: \n" ); document.write( "x = sqrt(14) \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "stan H. \n" ); document.write( " |