document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37390>Question 37390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3a+6b=-15<BR>\n" );
document.write( "a=-2b-5\r<BR>\n" );
document.write( "\n" );
document.write( "Use the substitution method to solve the system. If its dependant or inconsistant, so indicate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23035 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23035\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the two equations<BR>\n" );
document.write( "3a + 6b = -15<BR>\n" );
document.write( "a = -2b -5<BR>\n" );
document.write( "we will substitute the value given for a in the second equation in for the a in the first equation and get<BR>\n" );
document.write( "3(-2b - 5) + 6b = -15<BR>\n" );
document.write( "-6b - 15 + 6b = -15<BR>\n" );
document.write( "-15 = -15<BR>\n" );
document.write( "Since this is always true, we know we have a dependent syatem with an infinite number of solutions.  This means that the two equations represent the same line. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );