document.write( "Question 321410: 1) A silversmith has two alloys, one containing 30% silver and the other,55%. How much of each should be melted and combined to obtain 100 grams containing 45% silver?\r
\n" ); document.write( "\n" ); document.write( "2) A cellular phone company charges customers a certain amount for the first minute of a long distance call and an additional amount for each suceeding ...minute. A customer makes two calls to the same city, a 33-minute call for Php 269 and a 19-minute for Php 157. How much does the cellular phone company charge for the first minute? for each succeding minute?\r
\n" ); document.write( "\n" ); document.write( "3) A swimming pool can be filled by three water pipes, A,B and C. Pipe C alone can fill the pool in 8 hours. If pipes B and C are used together, the pool can be filled in 6 hours. If pipes A and B are used together, it takes 10 hours. How long does it take to fill the pool if all three pipes are used?\r
\n" ); document.write( "\n" ); document.write( "i need ur help!
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Algebra.Com's Answer #230343 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
1.A silversmith has two alloys, one containing 30% silver and the other, 55%.
\n" ); document.write( " How much of each should be melted and combined to obtain 100 grams containing 45% silver?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 55% alloy
\n" ); document.write( "Total amt will be 100 gr, therefore
\n" ); document.write( "(100-x) = amt of 30% alloy required
\n" ); document.write( "A typical mixture equation, using decimals
\n" ); document.write( ".55x + .30(100-x) = .45(100)
\n" ); document.write( ".55x + 30 - .30x = 45
\n" ); document.write( ".55x - .30x = 45 - 30
\n" ); document.write( ".25x = 15
\n" ); document.write( "x = \"15%2F.25\"
\n" ); document.write( "x = 60 gr of 55% alloy
\n" ); document.write( "then
\n" ); document.write( "100 - 60 = 40 gr of 30% alloy
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\n" ); document.write( ":
\n" ); document.write( "2) A cellular phone company charges customers a certain amount for the first
\n" ); document.write( " minute of a long distance call and an additional amount for each succeeding minute.
\n" ); document.write( " A customer makes two calls to the same city, a 33-minute call for Php 269
\n" ); document.write( " and a 19-minute for Php 157.
\n" ); document.write( "How much does the cellular phone company charge for the first minute? for each succeeding minute?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt charged for 1st min
\n" ); document.write( "Let y = amt charged for each succeeding min
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\n" ); document.write( "Call 1: x + 32y = 269
\n" ); document.write( "Call 2: x + 18y = 157
\n" ); document.write( "-----------------------Subtraction eliminates x, find y
\n" ); document.write( "\" \"0x + 14y = 112
\n" ); document.write( "y = \"112%2F14\"
\n" ); document.write( "y = 8 cents for each succeeding min
\n" ); document.write( "I'll let you find the value of x, the first minute cost
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\n" ); document.write( "3) A swimming pool can be filled by three water pipes, A,B and C.
\n" ); document.write( " Pipe C alone can fill the pool in 8 hours.
\n" ); document.write( "If pipes B and C are used together, the pool can be filled in 6 hours.
\n" ); document.write( " If pipes A and B are used together, it takes 10 hours.
\n" ); document.write( " How long does it take to fill the pool if all three pipes are used?
\n" ); document.write( ":
\n" ); document.write( "Let the completed job = 1 (a full pool)
\n" ); document.write( ":
\n" ); document.write( "\"pipes B and C are used together, the pool can be filled in 6 hours.\"
\n" ); document.write( "\"6%2FB\" + \"6%2FC\" = 1
\n" ); document.write( "It tells us pipe C can do it in 8 hrs, therefore:
\n" ); document.write( "\"6%2FB\" + \"6%2F8\" = 1
\n" ); document.write( "multiply by 8B
\n" ); document.write( "8(6) + 6B = 8B
\n" ); document.write( "48 = 8B - 6B
\n" ); document.write( "48 = 2B
\n" ); document.write( "B = \"48%2F2\"
\n" ); document.write( "B = 24 hrs for B alone
\n" ); document.write( ":
\n" ); document.write( "\"If pipes A and B are used together, it takes 10 hours.\" we know B, therefore
\n" ); document.write( "\"10%2FA\" + \"10%2F24\" = 1
\n" ); document.write( "Multiply by 24A
\n" ); document.write( "24(10) + 10A = 24A
\n" ); document.write( ":
\n" ); document.write( "240 = 24A - 10A
\n" ); document.write( "240 = 14A
\n" ); document.write( "A = \"240%2F14\"
\n" ); document.write( "A = 17.143 hrs for A alone
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