document.write( "Question 321410: 1) A silversmith has two alloys, one containing 30% silver and the other,55%. How much of each should be melted and combined to obtain 100 grams containing 45% silver?\r
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document.write( "2) A cellular phone company charges customers a certain amount for the first minute of a long distance call and an additional amount for each suceeding ...minute. A customer makes two calls to the same city, a 33-minute call for Php 269 and a 19-minute for Php 157. How much does the cellular phone company charge for the first minute? for each succeding minute?\r
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document.write( "3) A swimming pool can be filled by three water pipes, A,B and C. Pipe C alone can fill the pool in 8 hours. If pipes B and C are used together, the pool can be filled in 6 hours. If pipes A and B are used together, it takes 10 hours. How long does it take to fill the pool if all three pipes are used?\r
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document.write( "i need ur help! \n" );
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Algebra.Com's Answer #230343 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1.A silversmith has two alloys, one containing 30% silver and the other, 55%. \n" ); document.write( " How much of each should be melted and combined to obtain 100 grams containing 45% silver? \n" ); document.write( ": \n" ); document.write( "Let x = amt of 55% alloy \n" ); document.write( "Total amt will be 100 gr, therefore \n" ); document.write( "(100-x) = amt of 30% alloy required \n" ); document.write( "A typical mixture equation, using decimals \n" ); document.write( ".55x + .30(100-x) = .45(100) \n" ); document.write( ".55x + 30 - .30x = 45 \n" ); document.write( ".55x - .30x = 45 - 30 \n" ); document.write( ".25x = 15 \n" ); document.write( "x = \n" ); document.write( "x = 60 gr of 55% alloy \n" ); document.write( "then \n" ); document.write( "100 - 60 = 40 gr of 30% alloy \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "2) A cellular phone company charges customers a certain amount for the first \n" ); document.write( " minute of a long distance call and an additional amount for each succeeding minute. \n" ); document.write( " A customer makes two calls to the same city, a 33-minute call for Php 269 \n" ); document.write( " and a 19-minute for Php 157. \n" ); document.write( "How much does the cellular phone company charge for the first minute? for each succeeding minute? \n" ); document.write( ": \n" ); document.write( "Let x = amt charged for 1st min \n" ); document.write( "Let y = amt charged for each succeeding min \n" ); document.write( ": \n" ); document.write( "Call 1: x + 32y = 269 \n" ); document.write( "Call 2: x + 18y = 157 \n" ); document.write( "-----------------------Subtraction eliminates x, find y \n" ); document.write( "\" \"0x + 14y = 112 \n" ); document.write( "y = \n" ); document.write( "y = 8 cents for each succeeding min \n" ); document.write( "I'll let you find the value of x, the first minute cost \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "3) A swimming pool can be filled by three water pipes, A,B and C. \n" ); document.write( " Pipe C alone can fill the pool in 8 hours. \n" ); document.write( "If pipes B and C are used together, the pool can be filled in 6 hours. \n" ); document.write( " If pipes A and B are used together, it takes 10 hours. \n" ); document.write( " How long does it take to fill the pool if all three pipes are used? \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 (a full pool) \n" ); document.write( ": \n" ); document.write( "\"pipes B and C are used together, the pool can be filled in 6 hours.\" \n" ); document.write( " \n" ); document.write( "It tells us pipe C can do it in 8 hrs, therefore: \n" ); document.write( " \n" ); document.write( "multiply by 8B \n" ); document.write( "8(6) + 6B = 8B \n" ); document.write( "48 = 8B - 6B \n" ); document.write( "48 = 2B \n" ); document.write( "B = \n" ); document.write( "B = 24 hrs for B alone \n" ); document.write( ": \n" ); document.write( "\"If pipes A and B are used together, it takes 10 hours.\" we know B, therefore \n" ); document.write( " \n" ); document.write( "Multiply by 24A \n" ); document.write( "24(10) + 10A = 24A \n" ); document.write( ": \n" ); document.write( "240 = 24A - 10A \n" ); document.write( "240 = 14A \n" ); document.write( "A = \n" ); document.write( "A = 17.143 hrs for A alone \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( " |