document.write( "Question 37381: log(7-2x)=log(x+5) \n" ); document.write( "

Algebra.Com's Answer #23030 by fractalier(6550) $\"\"$ $\"About$

You can put this solution on YOUR website!
Since log(7 - 2x) = log(x + 5), we can exponentiate both sides, thus putting the arguments equal...thus we have
\n" ); document.write( "7 - 2x = x + 5 and
\n" ); document.write( "3x = 2 and
\n" ); document.write( "x = 2/3
\n" ); document.write( "Check to be sure this is a legal solution...it is, so
\n" ); document.write( "x = 2/3 \n" ); document.write( "

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