document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321511>Question 321511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It is necessary to have a 40% antifreeze solution in the radiator of a certian car. The radiator now has 60 liters of 20% solution. How many liters of this should be drained and replaced with 100% antifreeze to get the desired strength? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230288 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230288\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tank contains 60 liters  - 20%<BR>\n" );
document.write( "let the amount to be drained be x liters<BR>\n" );
document.write( "Balance will be 60-x liters --20%<BR>\n" );
document.write( "100% added will be x liters<BR>\n" );
document.write( "total will be 60 liters 40%<BR>\n" );
document.write( "..<BR>\n" );
document.write( "concentration equation<BR>\n" );
document.write( "1x+0.2(60-x)=60*0.4<BR>\n" );
document.write( "1x+12-0.2x=24<BR>\n" );
document.write( "0.8x=12<BR>\n" );
document.write( "x=12/0.8<BR>\n" );
document.write( "x=15 liters will have to be drained\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );