document.write( "Question 321540: i really just need this couple more questions to finish my exam: plz help...
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document.write( "1. 3√2 + √50
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document.write( "2.(√3-√5)(√3-√5)\r
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document.write( "3. √m √m squared (the last m is sqaured)\r
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document.write( "4. 3 √13/√3 (the / means over √3 \n" );
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Algebra.Com's Answer #230271 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1. 3√2 + √50 \n" ); document.write( "--- \n" ); document.write( "= 3*sqrt(2) + sqrt(25*2) \n" ); document.write( "--- \n" ); document.write( "= 3*sqrt(2) + 5*sqtt(2) \n" ); document.write( "--- \n" ); document.write( "= 8*sqrt(2) \n" ); document.write( "===================================\r \n" ); document.write( "\n" ); document.write( "2.(√3-√5)(√3-√5) \n" ); document.write( "= 3 - 2*sqrt(15) + 5 \n" ); document.write( "---- \n" ); document.write( "= 8 - 2*sqrt(15) \n" ); document.write( "===================================\r \n" ); document.write( "\n" ); document.write( "3. √m √m squared (the last m is sqaured) \n" ); document.write( "--- \n" ); document.write( "= sqrt(m)*sqrt(m^2) \n" ); document.write( "--- \n" ); document.write( "= |m|*sqrt(m) \n" ); document.write( "=================================== \r \n" ); document.write( "\n" ); document.write( "4. 3 √13/√3 (the / means over √3\r \n" ); document.write( "\n" ); document.write( "------------- \n" ); document.write( "= [3*sqrt(13))/sqrt(3) \n" ); document.write( "--- \n" ); document.write( "= [3*sqrt(39))/3 \n" ); document.write( "--- \n" ); document.write( "= sqrt(39) \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========================== \n" ); document.write( " |