document.write( "Question 321541: factor completely x^3+7x^2-5x-35 \n" ); document.write( "
Algebra.Com's Answer #230266 by jim_thompson5910(35256)\"\" \"About 
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\"x%5E3%2B7x%5E2-5x-35\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E3%2B7x%5E2%29%2B%28-5x-35%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%28x%2B7%29-5%28x%2B7%29\" Factor out the GCF \"x%5E2\" out of the first group. Factor out the GCF \"-5\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-5%29%28x%2B7%29\" Since we have the common term \"x%2B7\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E3%2B7x%5E2-5x-35\" factors to \"%28x%5E2-5%29%28x%2B7%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E3%2B7x%5E2-5x-35=%28x%5E2-5%29%28x%2B7%29\"
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