document.write( "Question 321510: What is the maximum area of a rectangle given that its perimeter is 32 feet?
\n" ); document.write( "Choices... 32ft, 128ft, 256ft, or 64ft.\r
\n" ); document.write( "\n" ); document.write( "I tried 12 by 4 but i did not work. And I tried 15 by 2. I dont know any other ways to solve for this question.
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Algebra.Com's Answer #230254 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
2L + 2W = 32 ___ L + W = 16 ___ L = 16 - W\r
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\n" ); document.write( "\n" ); document.write( "A = L * W = (16 - W)W = 16W - W^2 ___ this is a downward opening parabola with the maximum for A at the vertex
\n" ); document.write( "___ the vertex is on the axis of symmetry\r
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\n" ); document.write( "\n" ); document.write( "W = -b / 2a = -16 / [2*(-1)] = 8\r
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\n" ); document.write( "\n" ); document.write( "A = (16 - 8)8 = 64\r
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\n" ); document.write( "\n" ); document.write( "the rectangle with the maximum area is a square
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