document.write( "Question 321342: Hi, I am having a problem with two variables on a dividend when dividing polynomials. My exact problem is:\r
\n" ); document.write( "\n" ); document.write( "2x^3-9x^2y-12y^3+17xy^2 divided by 2x-3y\r
\n" ); document.write( "\n" ); document.write( "I know the usual process and I have gotten to the second equation involving getting a difference of -6x^2y but now I am stuck, because when I divide -6x^2y to the first term of the divisor, I have to multiply that quotient (which is -3xy) to the brought-down -12y^3, and as far as I remember I can't multiply it because -12y^3 has no x variable. Can you please help? Thanks. \n" ); document.write( "

Algebra.Com's Answer #230243 by scott8148(6628) $\"\"$ $\"About$

You can put this solution on YOUR website!
arrange the terms in descending power hierarchy for one of the variables (x seems easiest)\r
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\n" ); document.write( "\n" ); document.write( "(2x-3y) into (2x^3 - 9x^2 y + 17x y^2 - 12y^3)\r
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\n" ); document.write( "\n" ); document.write( "___ 2x into 2x^3 gives x^2 ___ x^2(2x-3y) is (2x^3-3x^2 y)\r
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\n" ); document.write( "\n" ); document.write( "___ 2x into (-6x^2 y) gives -3xy ___ -3xy(2x-3y) is (-6x^2 y + 9x y^2)\r
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\n" ); document.write( "\n" ); document.write( "___ 2x into (8x y^2) gives 4y^2 ___ 4y^2(2x-3y) is (8x y^2 - 12y^3)\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 3xy + 4y^2 \n" ); document.write( "

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