document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321483>Question 321483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The capacity of a car radiator is 18 quarts. If it is full of a 20% antifreeze solution, how many quarts must be drained off and replaced by a 100% solution to give 18 quarts of a 39% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230234 by </B><A HREF=/tutors/aboutme.mpl?userid=galactus><B>galactus(183)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=galactus><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=galactus><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount being drained.\r<BR>\n" );
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document.write( "Original 20% mixture minus amount drained is .20(18-x).\r<BR>\n" );
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document.write( "Pure antifreeze added back is x.\r<BR>\n" );
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document.write( "New 39% mixture is .39(18)\r<BR>\n" );
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document.write( "So, we solve the equation\r<BR>\n" );
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document.write( ".20(18-x)+x=.39(18)\r<BR>\n" );
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document.write( "x=4.275 quarts should be drained and replaced with pure antifreeze.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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