document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321431>Question 321431</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 8 o'clock, the hour hand and the minute hand are perpendicular. They form <BR>\n" );
document.write( "straight line 16 4/11 minutes later. How many minutes after 9 o'clock are they<BR>\n" );
document.write( "perpendicular again?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230231 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230231\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At 9 o'clock ... not 8\r<BR>\n" );
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document.write( "the hour hand moves 1/12 of a circle in 60 min ___ 1/2º per min\r<BR>\n" );
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document.write( "the minute hand moves 360º in 60 min ___ 6º per min\r<BR>\n" );
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document.write( "the starting angle is 90º ___ the hands will be perpendicular again when that angle is 270º\r<BR>\n" );
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document.write( "90 - (1/2)m + 6m = 270 ___ (11/2)m = 180 ___ m = 360/11 = 32 8/11 min\r<BR>\n" );
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document.write( "the wording of the problem shows that the angle increases 90º every 16 4/11 min<BR>\n" );
document.write( "___ 2 * (16 4/11) = 32 8/11 </SPAN>\n" );
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