document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321341>Question 321341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I am having a problem with two variables on a dividend when dividing polynomials. My exact problem is:\r<BR>\n" );
document.write( "\n" );
document.write( "2x^3-9x^2y-12^y+17xy^2 divided by 2x-3y\r<BR>\n" );
document.write( "\n" );
document.write( "I know the usual process and I have gotten to the second equation involving getting a difference of -6x^2y but now I am stuck, because when I divide -6x^2y to the first term of the divisor, I have to multiply that quotient (which is -3xy) to the brought-down -12y^3, and as far as I remember I can't multiply it because -12y^3 has no x variable. Can you please help? Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230193 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230193\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> My exact problem is:<BR>\n" );
document.write( "2x^3-9x^2y-12^y+17xy^2 divided by 2x-3y <BR>\n" );
document.write( ":<BR>\n" );
document.write( "Rearrange the number divided, then the long division procedure will work<BR>\n" );
document.write( ":<BR>\n" );
document.write( ".................______________________________<BR>\n" );
document.write( "(2x-3y)|2x^3 - 9x^2y + 17xy^2 - 12y^3<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
document.write( "I got a quotient of: x^2 - 3xy - y^2, remainder -15y^3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );