document.write( "Question 321405: 15-(2/3)x>-5 ? can you help me solve for the x? the answer is {x<30} but how do I get to that point?\r
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document.write( "thanks \n" );
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Algebra.Com's Answer #230192 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 15-(2/3)x > -5 \n" ); document.write( "Add 5 \n" ); document.write( "20 - (2/3)x > 0 \n" ); document.write( "Add (2/3)x \n" ); document.write( "20 > (2/3)x \n" ); document.write( "(2/3)x < 20 \n" ); document.write( "Multiply by 3 \n" ); document.write( "2x < 60 \n" ); document.write( "Divide by 2 \n" ); document.write( "x < 30 \n" ); document.write( "That's one way. \n" ); document.write( "--------------- \n" ); document.write( " \n" ); document.write( " |