document.write( "Question 321405: 15-(2/3)x>-5 ? can you help me solve for the x? the answer is {x<30} but how do I get to that point?\r
\n" ); document.write( "\n" ); document.write( "thanks
\n" ); document.write( "

Algebra.Com's Answer #230192 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
15-(2/3)x > -5
\n" ); document.write( "Add 5
\n" ); document.write( "20 - (2/3)x > 0
\n" ); document.write( "Add (2/3)x
\n" ); document.write( "20 > (2/3)x
\n" ); document.write( "(2/3)x < 20
\n" ); document.write( "Multiply by 3
\n" ); document.write( "2x < 60
\n" ); document.write( "Divide by 2
\n" ); document.write( "x < 30
\n" ); document.write( "That's one way.
\n" ); document.write( "---------------
\n" ); document.write( "
\n" ); document.write( "
\n" );