document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37373>Question 37373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have tried to figure these out many times,I would just like to check my answers here's what I have.Any help will be greatly appreciated.\r<BR>\n" );
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document.write( "Solve the following equations.<BR>\n" );
document.write( "A) (sqrt of x)-2=1<BR>\n" );
document.write( "   ((sqrtof x)-2)^2 = 1^2<BR>\n" );
document.write( "    x-2=1<BR>\n" );
document.write( "    x=3\r<BR>\n" );
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document.write( "B) sqrt of x^3=27<BR>\n" );
document.write( "   (sqrt of x^3)^2 = 27^2<BR>\n" );
document.write( "    x^3=729<BR>\n" );
document.write( "    x=9\r<BR>\n" );
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document.write( "C) cuberoot of x^2=9<BR>\n" );
document.write( "   (cuberoot of x^2)^3= 9^3<BR>\n" );
document.write( "    x^2=729<BR>\n" );
document.write( "    x=27 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23018 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23018\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> B and C are correct.<BR>\n" );
document.write( "In A however, (sqrt of x) - 2 = 1, you want to isolate the root BEFORE squaring both sides, so<BR>\n" );
document.write( "sqrt of x = 3 and<BR>\n" );
document.write( "x = 9<BR>\n" );
document.write( "Now if you meant sqrt of (x - 2) = 1, then the answer is 3.  Notice the difference. </SPAN>\n" );
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