document.write( "Question 321344: URGENT!\r
\n" ); document.write( "\n" ); document.write( "1.While waiting for a train, alvin takes a bus ride at 60 kph to a certain point and then take walks back leisurely at 10 kph. The bus takes 1/4 hour less than his walking. How far does he walk and how long.\r
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Algebra.Com's Answer #230163 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
.While waiting for a train, alvin takes a bus ride at 60 kph to a certain point
\n" ); document.write( " and then take walks back leisurely at 10 kph. The bus takes 1/4 hour less than his walking.
\n" ); document.write( " How far does he walk and how long.
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\n" ); document.write( "Let t = time he walked
\n" ); document.write( "then
\n" ); document.write( "(t-.25) = time rode; (changed 1/4 to .25)
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\n" ); document.write( "Write a distance equation; dist = speed * time
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\n" ); document.write( "riding dist = walking dist
\n" ); document.write( "60(t-.25) = 10t
\n" ); document.write( "60t - 15 = 10t
\n" ); document.write( "60t - 10t = 15
\n" ); document.write( "50t = 15
\n" ); document.write( "t = \"15%2F50\"
\n" ); document.write( "t = .3 hrs, which is .3*60 = 18, min is time he walked
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\n" ); document.write( "Find the dist
\n" ); document.write( "10 * .3 = 3 km he walked, (and rode)
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\n" ); document.write( "Confirm our solutions by finding the dist he rode
\n" ); document.write( "(.3-.25) * 60 =
\n" ); document.write( ".05 * 60 = 3 km also
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