document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37261>Question 37261</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that a particular computer depreciates 50% in value each year and has an original cost of<BR>\n" );
document.write( "$4,000. in what year will the value of the computer become $100 or less? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23016 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23016\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well for this one you can go ahead and list each yearly value of the computer, taking half its value each year:<BR>\n" );
document.write( "$4000, $2000, $1000, $500, $250, $125, $62.50<BR>\n" );
document.write( "So you can see that after six years, its value is under $100.<BR>\n" );
document.write( "In general, you would use exponents and/or logarithms to solve a problem such as this. </SPAN>\n" );
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