document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321345>Question 321345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> urgent!!!!!!!!!!! URGENT!!!!!!!!!!!! UrGeNt!!!!!!!!!!!!!!!!! uRgEnt!!!!!!!!!!!!!\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "1. a chemist has 400 grams of salt solution that is 10% salt. How many grams of 20% salt solution must be added to obtain a 12% solution of salt?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2. How much salt must be added to 800 grams of a solution that is 15% to obtain a solution that is 20% salt.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "3. What should be the alcohol content a winemaker must add to 10 gallons of wine that is 12% alcohol to have 15 gallons of wine that is 14% alcohol?\r<BR>\n" );
document.write( "\n" );
document.write( "4. A chemist mixes a 200 L of a solution that is 60% acid with a 300 L of a solution that is 20% acid. What is the percentage of the mixture.\r<BR>\n" );
document.write( "\n" );
document.write( "5. How much water must be added to 20 L of a 10% solution of boric acid to reduce it to a 4% solution/\r<BR>\n" );
document.write( "\n" );
document.write( "6. How many liters of pure acid should be added to 25 liters of a 60% solution of acid to obtain a 75% acid solution?\r<BR>\n" );
document.write( "\n" );
document.write( "7. How many grams of water must be evaporated from 100 kilograms of a 40% salt solution to produce a 50% salt solution?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "urgent!!!!!!!!!!! URGENT!!!!!!!!!!!! UrGeNt!!!!!!!!!!!!!!!!! uRgEnt!!!!!!!!!!!!!\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230157 by </B><A HREF=/tutors/aboutme.mpl?userid=Dummy+Alphabet><B>Dummy Alphabet(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Dummy+Alphabet><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Dummy+Alphabet><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> •	1) Let the amount to be added be x grams.\r<BR>\n" );
document.write( "\n" );
document.write( "0.1 (400) + 0.2x = 0.12( 400 + x)\r<BR>\n" );
document.write( "\n" );
document.write( "40 + 0.2x = 48 + 0.12x\r<BR>\n" );
document.write( "\n" );
document.write( "0.2x - 0.12x = 48 - 40 = 8\r<BR>\n" );
document.write( "\n" );
document.write( "0.08x = 8<BR>\n" );
document.write( "x = 8/0.08 = 100 grams ANSWER \r<BR>\n" );
document.write( "\n" );
document.write( "2) 0.15( 800) + x = 0.2 ( 800 +x)\r<BR>\n" );
document.write( "\n" );
document.write( "120 + x = 160 + 0.2x\r<BR>\n" );
document.write( "\n" );
document.write( "0.8x = 40<BR>\n" );
document.write( "x = 40/0.8 = 50 grams ANSWER\r<BR>\n" );
document.write( "\n" );
document.write( "3) 0.12(10) + 5x = 0.14 ( 15)\r<BR>\n" );
document.write( "\n" );
document.write( "1.2 + 5x = 2.1<BR>\n" );
document.write( "5x = 0.9<BR>\n" );
document.write( "x = 0.9/5 = 0.18 \r<BR>\n" );
document.write( "\n" );
document.write( "Answer is 5 gallons of 18% alcohol \r<BR>\n" );
document.write( "\n" );
document.write( "4) 0.6 (200) = 120<BR>\n" );
document.write( "0.2(300) =60<BR>\n" );
document.write( "total 500 = 180<BR>\n" );
document.write( "180/500 X 100 = 36% acid \r<BR>\n" );
document.write( "\n" );
document.write( "5) 0.1(20) = .04 ( 20 + x)\r<BR>\n" );
document.write( "\n" );
document.write( "2 = 0.8 + 0.04x\r<BR>\n" );
document.write( "\n" );
document.write( "1.2 = 0.04x<BR>\n" );
document.write( "x = 1.2/0.04 = 30 litres\r<BR>\n" );
document.write( "\n" );
document.write( "6) 0.6( 25) + x = 0.75 ( 25 + x)<BR>\n" );
document.write( "15+ x = 18.75 + 0.75x<BR>\n" );
document.write( "3.75 = 0.25x<BR>\n" );
document.write( "x = 3.75/0.25 = 375/25 = 15 litres\r<BR>\n" );
document.write( "\n" );
document.write( "7) 40% of 100 = 40 kilos<BR>\n" );
document.write( "To get 50% solution answer is 100 - 80 = 20 kilograms\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "hehehe </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );