document.write( "Question 321319: what is the standard form for the equation of the line which passes through the point (5, 2) and which has a y-intercept of 7. \r
\n" ); document.write( "\n" ); document.write( "what is the standard form for the equation of the line which passes through the point (–1, –2) and is parallel to the line that has an equation of 6x + 2y = 4.
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Algebra.Com's Answer #230131 by jim_thompson5910(35256)\"\" \"About 
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I'll do the first problem to get you started.\r
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\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"7\" which goes through the point (5,2), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-2=7%28x-5%29\" Plug in \"m=7\", \"x%5B1%5D=5\", and \"y%5B1%5D=2\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-2=7x%2B%287%29%28-5%29\" Distribute \"7\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-2=7x-35\" Multiply \"7\" and \"-5\" to get \"-35\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=7x-35%2B2\" Add 2 to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=7x-33\" Combine like terms \"-35\" and \"2\" to get \"-33\" \r
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\n" ); document.write( "\n" ); document.write( "\"-7x%2By=-33\" Now subtract 7x from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"7x-y=33\" Multiply EVERY term by -1 to make the x coefficient positive.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line, in standard form, with a slope of \"7\" which goes through the point (5,2) is \"7x-y=33\"
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