document.write( "Question 321197: Over the last three years, Salesperson A has earned twice as much as Salesperson B, who in turn has averaged 50% more than Salesperson C. The three combined to make $220,000 over the three years. How much did Salesperson B earn on average in any year? \n" ); document.write( "
Algebra.Com's Answer #230086 by checkley77(12844)\"\" \"About 
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A=2B
\n" ); document.write( "B=1.5C OR C=B/1.5
\n" ); document.write( "A+B+C=220,000
\n" ); document.write( "2B+B+B/1.5=220,000
\n" ); document.write( "3B+B/1.5=220,000
\n" ); document.write( "(3B*1.5+B)/1.5=220,000
\n" ); document.write( "(4.5B+B)/1.5=220,000
\n" ); document.write( "5.5B/1.2=220,000 CROSS MULTIPLY
\n" ); document.write( "5.5B=220,000*1,5
\n" ); document.write( "5.5B=330,000
\n" ); document.write( "B=330,000/5.5
\n" ); document.write( "B=$60,000 WAS B'S SALARY OVER 3 YEARS..
\n" ); document.write( "A=2*60,000=$120,000 WAS A'S SALARY.
\n" ); document.write( "C=60,000/1.5=$40,000 WAS C'S SALARY.
\n" ); document.write( "PROOF:
\n" ); document.write( "60,000+120,000+40,000=220,000
\n" ); document.write( "220,000=220,000
\n" ); document.write( "B'S AVERAGE YEARLY SALARY WAS 60,000/3=$20,000 ANS.
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