document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321210>Question 321210</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are complentary if their sum is 90 degrees.  If measure of the 1st angle is x degree, and the measure of the second angle is (3x-2); find measure of each angle.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #230081 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=230081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+(3X-2)=90<BR>\n" );
document.write( "X+3X-2=90<BR>\n" );
document.write( "4X=90+2<BR>\n" );
document.write( "4X=92<BR>\n" );
document.write( "X=92/4<BR>\n" );
document.write( "X=23 DEGREES FOR THE SMALLER ANGLE.<BR>\n" );
document.write( "3X-2=3*23-2=69-2=67 DEGREES FOR THE LARGER ANGLE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "23+57=90<BR>\n" );
document.write( "90=90 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );