document.write( "Question 321154: A merchant blends tea that sells for $3.00 a pound with tea that sells for $2.75 a pound to produce 80 pound of a mixture that sells for $2.90 a pound. How many pounds of each type of tea does the merchant use in the blend. \n" ); document.write( "

Algebra.Com's Answer #230015 by josmiceli(19441) $\"\"$ $\"About$

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$\"a+\"$ = pounds of $3/lb tea
\n" ); document.write( " $\"b\"$ = pounds of $2.75/lb tea
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"a+%2B+b+=+80\"$
\n" ); document.write( "---------
\n" ); document.write( " $\"%283a+%2B+2.75b%29%2F80+=+2.9\"$
\n" ); document.write( " $\"3a+%2B+2.75b+=+2.9%2A80\"$
\n" ); document.write( "(2) $\"3a+%2B+2.75b+=+232\"$
\n" ); document.write( "Multiply both sides of (1) by $\"2.75\"$
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) $\"3a+%2B+2.75b+=+232\"$
\n" ); document.write( "(1) $\"-2.75a+-+2.75b+=+-+220\"$
\n" ); document.write( " $\".25a+=+12\"$
\n" ); document.write( " $\"a+=+48\"$
\n" ); document.write( "and, since
\n" ); document.write( " $\"a+%2B+b+=+80\"$
\n" ); document.write( " $\"b+=+32\"$
\n" ); document.write( "The merchant needs 48 pounds of $3/lb tea and
\n" ); document.write( "32 pounds of $2.75/lb tea \n" ); document.write( "

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