document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37318>Question 37318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Combine like terms. \r<BR>\n" );
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document.write( "x + 6y + 15 - 7x - 3y - 13  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23001 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23001\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From x + 6y + 15 - 7x - 3y - 13, we add all of the x's together, all of the y's together, and all of the number (or constant) terms together.  Thus,<BR>\n" );
document.write( "x + 6y + 15 - 7x - 3y - 13 =<BR>\n" );
document.write( "(x - 7x) + (6y - 3y) + (15 - 13) =<BR>\n" );
document.write( "-6x + 3y + 2 </SPAN>\n" );
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