document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321160>Question 321160</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given that log 8=0.9031 and log 9=0.9542 and obviously log 10=1, which logarithm cannot be found without the use of a calculator?\r<BR>\n" );
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document.write( "a. log 17 b. log (5/4) c. log 15 d. log 600 e. log 0.4 \r<BR>\n" );
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document.write( "and also if you could show the work as how you got the answer. thank you so much :)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229995 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> given that log 8=0.9031 and log 9=0.9542 and obviously log 10=1, which logarithm cannot be found without the use of a calculator?<BR>\n" );
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document.write( "If log8 = 0.9031, then log 2^3 = 0.9031 and 3log2 = 0.9031<BR>\n" );
document.write( "Then log(2) = (0.9031/3) = 0.3010<BR>\n" );
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document.write( "If log9 = 0.9542, then 2log(3) = 0.9542<BR>\n" );
document.write( "Then log(3) = 0.9542/2 = 0.4771<BR>\n" );
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document.write( "So now you know the following:<BR>\n" );
document.write( "log(2) = 0.3010<BR>\n" );
document.write( "log(3) = 0.4771<BR>\n" );
document.write( "log(8) = 0.9031<BR>\n" );
document.write( "log(9) = 0.9542<BR>\n" );
document.write( "log(10) = 1<BR>\n" );
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document.write( "a. log 17 cannot be done with the above information <BR>\n" );
document.write( "b. log (5/4) = log(10/8) = log(10)-log(8) <BR>\n" );
document.write( "c. log 15 = log[3(10/2)] = log(3)+log(10)-log(2) <BR>\n" );
document.write( "d. log 600 = log[2*3*2^2*5^2] so can be done <BR>\n" );
document.write( "e. log 0.4 = log[(2^2)/10] = 2log(2) - log(10)\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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