document.write( "Question 321157: What is the equation of a line that is perpendicular to 7x+8y-12=0 and passes through (-2,5)? \n" ); document.write( "
Algebra.Com's Answer #229983 by mananth(16946) You can put this solution on YOUR website! 7x+8y-12=0 \n" ); document.write( "8y=-7x+12 \n" ); document.write( "y=-7/8 x +12/8 \n" ); document.write( ".. \n" ); document.write( "slope = -7/8 \n" ); document.write( "the perpendicular to this line will have a slope of of 8/7 \n" ); document.write( "This line passes through (-2,5) \n" ); document.write( "equation of line in slope intercept form = \n" ); document.write( "y-y1= m(x-x1) \n" ); document.write( "y-(-2)= 8/7(x-5) \n" ); document.write( "y+2=8/7(x-5) \n" ); document.write( "7(y+2)=8(x-5) \n" ); document.write( "7y+14=8x-40 \n" ); document.write( "7y=8x-56 \n" ); document.write( "y=(8/7)x -8 is the equation of the required line \n" ); document.write( " |