document.write( "Question 321157: What is the equation of a line that is perpendicular to 7x+8y-12=0 and passes through (-2,5)? \n" ); document.write( "
Algebra.Com's Answer #229983 by mananth(16946)\"\" \"About 
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7x+8y-12=0
\n" ); document.write( "8y=-7x+12
\n" ); document.write( "y=-7/8 x +12/8
\n" ); document.write( "..
\n" ); document.write( "slope = -7/8
\n" ); document.write( "the perpendicular to this line will have a slope of of 8/7
\n" ); document.write( "This line passes through (-2,5)
\n" ); document.write( "equation of line in slope intercept form =
\n" ); document.write( "y-y1= m(x-x1)
\n" ); document.write( "y-(-2)= 8/7(x-5)
\n" ); document.write( "y+2=8/7(x-5)
\n" ); document.write( "7(y+2)=8(x-5)
\n" ); document.write( "7y+14=8x-40
\n" ); document.write( "7y=8x-56
\n" ); document.write( "y=(8/7)x -8 is the equation of the required line
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