document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321141>Question 321141</A>: <I><SPAN STYLE=\"word-break: break-all;\">  I need help to solve by substitution or addition, whichever one is easier. Please show me in detail how to work this problem.\r<BR>\n" );
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document.write( "2y - x = 3<BR>\n" );
document.write( "x = 3y - 5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229973 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2y - x = 3<BR>\n" );
document.write( "x = 3y - 5<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2y-x=3<BR>\n" );
document.write( "x-3y=-5<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Add both the equations<BR>\n" );
document.write( "2y-x+x-3y=3-5<BR>\n" );
document.write( "-y=-2<BR>\n" );
document.write( "y=-2/-1<BR>\n" );
document.write( "y=2<BR>\n" );
document.write( "plug the value of y in any of the equations<BR>\n" );
document.write( "2y-x=3<BR>\n" );
document.write( "2*2-x=3<BR>\n" );
document.write( "4-x=3<BR>\n" );
document.write( "-x=-4+3<BR>\n" );
document.write( "-x=-1<BR>\n" );
document.write( "x=1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );