document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321129>Question 321129</A>: <I><SPAN STYLE=\"word-break: break-all;\"> flat-panel monitor are such that its length is 3 in. more than its width. If the length were doubled and if the width were decreased by 1 the area would be increased by 150 in. squared. What are the length and width of the flat panel.\r<BR>\n" );
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document.write( "This is from beginning algebra book tenth edition, chapter 6.6 applications of quadratic equations. Do I need to solve this problem with the formula P=2L+2W or A=LW, then move into standard form. Once it's in standard form I can figure out the problem. Please Help! Not sure how to write out the problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229958 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229958\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "Let <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large w\"> represent the original width. Then <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large w\ +\ 3\"> must represent the original length.\r<BR>\n" );
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document.write( "The original area is then the original length times the original width:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ w^2\ +\ 3w\">\r<BR>\n" );
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document.write( "The increased length must then be <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 2w\ +\ 6\"> and the decreased width must then be <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large w\ -\ 1\">, so the new area must be:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 2w^2\ +\ 4w\ -\ 6\">\r<BR>\n" );
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document.write( "and this is <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE 150\text{ in^2}\"> larger than the original area, so:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 2w^2\ +\ 4w\ -\ 6\ =\ w^2\ +\ 3w\ +\ 150\">\r<BR>\n" );
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document.write( "And then in standard form:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ w^2\ +\ w\ -\ 156\ =\ 0\">\r<BR>\n" );
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document.write( "And you should be off to the races.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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