document.write( "Question 320970: A father is twice as old as his son. Ten years ago he was three times as old as his son.
\n" ); document.write( "a) If the son is x years old, determine the age of the father in terms of x.
\n" ); document.write( "b) Find the ages of the father and son ten years ago in terms of x.
\n" ); document.write( "c) What are their present ages. \n" ); document.write( "
Algebra.Com's Answer #229942 by ankor@dixie-net.com(22740)\"\" \"About 
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A father is twice as old as his son. Ten years ago he was three times as old as his son.
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\n" ); document.write( "a) If the son is x years old, determine the age of the father in terms of x.
\n" ); document.write( "f = 2x
\n" ); document.write( ":
\n" ); document.write( "b) Find the ages of the father and son ten years ago in terms of x.
\n" ); document.write( "f - 10 = 3(x - 10)
\n" ); document.write( "f - 10 = 3x - 30
\n" ); document.write( "f = 3x - 30 + 10
\n" ); document.write( "f = 3x - 20; father in terms of x, 10 years ago
\n" ); document.write( ":
\n" ); document.write( "c) What are their present ages.
\n" ); document.write( "replace f with 2x in the above equation
\n" ); document.write( "2x = 3x - 20
\n" ); document.write( "20 = 3x - 2x
\n" ); document.write( "20 = x
\n" ); document.write( "son is 20, then father is 40 \n" ); document.write( "
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