document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201453>Question 201453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a parade 2mi long is proceeding at 3 mph, how long will it take a runner, jogging at 6 mph, to travel from the front of the parade to the end of the parade?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229926 by </B><A HREF=/tutors/aboutme.mpl?userid=galactus><B>galactus(183)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=galactus><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=galactus><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The jogger travels the same distance as the parade plus the length of the parade.  The parade travels 3t miles. The jogger travels this distance to get to the front plus the length of the parade, which is 2 miles. So, we have\r<BR>\n" );
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document.write( "6t=3t+2\r<BR>\n" );
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document.write( "3t=2\r<BR>\n" );
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document.write( "t=2/3 hour or 40 minutes. </SPAN>\n" );
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