document.write( "Question 319913: 98207990,22=D^(2/3)
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Algebra.Com's Answer #229873 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"D%5E%282%2F3%29=98207990.22\"
\n" ); document.write( "\"D=%2898207990.22%29%5E%281.5%29\" or approximately,
\n" ); document.write( "\"D=973240639120.76\"\r
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