document.write( "Question 320904: 2p^3=7p \n" ); document.write( "
Algebra.Com's Answer #229818 by toidayma(44)\"\" \"About 
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2p^3 = 7p <-> 2p^3 - 7p = 0 <-> p(2p^2 -7) = 0 <-> p = 0 or (2p^2 -7) = 0
\n" ); document.write( "Take a look at 2p^2 - 7 = 0 <-> p^2 = 3.5 <-> p = +- sqrt(3.5)
\n" ); document.write( "So we have three roots of this equation: -sqrt(3.5), 0 and sqrt(3.5).
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