document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=320903>Question 320903</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (3c-2)^3-50=100\r<BR>\n" );
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document.write( "so far I have...<BR>\n" );
document.write( "(3c-2)^3=150<BR>\n" );
document.write( "3c^3 -8=150<BR>\n" );
document.write( "3c^3=158 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229816 by </B><A HREF=/tutors/aboutme.mpl?userid=toidayma><B>toidayma(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=toidayma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=toidayma><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, you have a problem in expanding the (3c-2)^3 = 3c^3 - 2^3. It is not correct. If you really want to expand it, it has to follow the formula: (x+y)^3 = x^3 + 3x^2y + 3xy^2 + y^3. But there is an easier way to solve this:<BR>\n" );
document.write( "(3c - 2)^3 = 150<BR>\n" );
document.write( "<-> (3c-2) = 150^(1/3) <BR>\n" );
document.write( "<-> 3c = 150^(1/3) + 2<BR>\n" );
document.write( "<-> c = (150^(1/3) + 2)/3<BR>\n" );
document.write( "I think this solution is much better.  </SPAN>\n" );
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