document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=320887>Question 320887</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A total of $4300 was invested, part of it at 5% interest and the remainder at 10%. If the total yearly interest amounted to $310, how much was invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229806 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> total of $4300 was invested,<BR>\n" );
document.write( "Let $x be invested at 5% interest <BR>\n" );
document.write( "remainder $4300-x at 10%.<BR>\n" );
document.write( "total yearly interest = $310<BR>\n" );
document.write( "..<BR>\n" );
document.write( "0.05x+0.1(4300-x)=310<BR>\n" );
document.write( "0.05x+430-0.1x=310<BR>\n" );
document.write( "multiply the equation by 100<BR>\n" );
document.write( "5x+43000-10x=31000<BR>\n" );
document.write( "-5x=-12000<BR>\n" );
document.write( "x= 2400<BR>\n" );
document.write( "$ 2400 invested at 5%<BR>\n" );
document.write( "Balance (4300-2400) = $1900 at 10%  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );