document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=320746>Question 320746</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Reggie is three less than four times his daughter's age. Reggie is 69; how old is his daughter?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229794 by </B><A HREF=/tutors/aboutme.mpl?userid=GreatDane><B>GreatDane(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=GreatDane><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, start by makings some \"let\" statements.\r<BR>\n" );
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document.write( "Let R = Reggie's Age.<BR>\n" );
document.write( "Let D = Daughter's Age.\r<BR>\n" );
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document.write( "Reggie is 3 years less than 4 times his daughter.\r<BR>\n" );
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document.write( "R = 4D - 3\r<BR>\n" );
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document.write( "We know Reggie is 69, so we can sub 69 for Reggie's age.\r<BR>\n" );
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document.write( "69 = 4D - 3<BR>\n" );
document.write( "Now solve for D. Start by adding 3 to each side.<BR>\n" );
document.write( "69 + 3 = 4D - 3 + 3<BR>\n" );
document.write( "72 = 4d<BR>\n" );
document.write( "Divide both sides by 4.<BR>\n" );
document.write( "18 = d\r<BR>\n" );
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document.write( "His daughter's age is 18.\r<BR>\n" );
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document.write( "Now she can register to vote. </SPAN>\n" );
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