document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=320870>Question 320870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Right triangle ABC has one leg of length 7cm and one leg length 11 cm. determine the length of the hypotenuse, the perimeter of the triangle and the area of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229782 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229782\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one leg  7cm <BR>\n" );
document.write( "other leg  11 cm.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "hypotenuse^2= 7^2+11^2<BR>\n" );
document.write( "H^2=49+121<BR>\n" );
document.write( "H^2=170<BR>\n" );
document.write( "H= sqrt 170<BR>\n" );
document.write( "Hypotenuse = 13.03 cm<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Perimeter = sum of all sides<BR>\n" );
document.write( "=7+11+13.03=31.03 cm<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Area of right triangle  = 1/2 *one leg * other leg<BR>\n" );
document.write( "=1/2 * 7*11<BR>\n" );
document.write( "38.5 cm^2<BR>\n" );
document.write( "..<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );