document.write( "Question 320851: From a pile of 100 pennies, 100 nickles , and 100 dimes . select 21 coins which have a total of exactly $1.00 . how many of each of the three types should be selected? \n" ); document.write( "
Algebra.Com's Answer #229774 by JBarnum(2146)![]() ![]() You can put this solution on YOUR website! p+n+d=21 \n" ); document.write( ".01p+.05n+.1d=100 \n" ); document.write( "if there are any pennies they have to be in 5,10,15,or 20 \n" ); document.write( "if there are 20 penies then only room for 1 more coin which cant add to 1.00 \n" ); document.write( "15 pennies then there are 6 coins left but even at 6 dimes thats only 0.75 \n" ); document.write( "10 pennies makes 11 coins left n+d=11 and .05n+.1d=.90 is a possibility \n" ); document.write( "5 pennies makes 16 coins left n+d=16 and .05n+.1d=.95 is a 2nd possibility \n" ); document.write( "according to the problem it seems there has to be a number for each coin \n" ); document.write( " \r
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