document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=320835>Question 320835</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose a 2% acid solution is mixed with a 3% acid solution. Find the percent of acid in the following mixture:\r<BR>\n" );
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document.write( "a mixture that contains 3 times more 2% acid solution than 3% acid solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229764 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose a 2% acid solution is mixed with a 3% acid solution. \r<BR>\n" );
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document.write( "Find the percent of acid in the following mixture: \r<BR>\n" );
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document.write( "a mixture that contains 3 times more 2% acid solution than 3% acid solution.<BR>\n" );
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document.write( "Let amt of 3% solution be \"x\".<BR>\n" );
document.write( "Then amt. of 2% xolution is \"3x\"<BR>\n" );
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document.write( "Quantity of solution = x+3x = 4x<BR>\n" );
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document.write( "Quantity of acid = 0.03x + 0.02(3x) = 0.03 + 0.06x = = 0.09x<BR>\n" );
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document.write( "Percent of acid = 0.09x/4x = 0.09/4 = 0.0225 = 2.25%<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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