document.write( "Question 320841: Hey folks, \r
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document.write( "Got a problem here. The area of a rectangle is 308 square feet, and is 8 feet longer than the width. My teacher has supplied the answer: 14 feet by 22 feet, but I can't figure out how to arrive at those numbers. Help!!!\r
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document.write( "Mike \n" );
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Algebra.Com's Answer #229754 by checkley77(12844) ![]() You can put this solution on YOUR website! AREA=LW \n" ); document.write( "Given: Area=308 & Length is the Width plus 8 (W+8). \n" ); document.write( "L=W+8 \n" ); document.write( "Replace L by (W+8) & solve for W. \n" ); document.write( "308=(W+8)W \n" ); document.write( "308=W^2+8W \n" ); document.write( "W^2+8W-308=0 \n" ); document.write( "(W+22)(W-14)=0 \n" ); document.write( "W-14=0 \n" ); document.write( "W=14 ANS. FOR THE WIDTH. \n" ); document.write( "14=W+8 \n" ); document.write( "L=14+8=22 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "308=22*14 \n" ); document.write( "308=308 \n" ); document.write( " \n" ); document.write( " |