document.write( "Question 320799: How can i use the rational root theorem and polynomail long division to factor the following completely? x^3+3x^2+3x+1 \n" ); document.write( "
Algebra.Com's Answer #229696 by Fombitz(32388)\"\" \"About 
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From the rational roots theorem,
\n" ); document.write( "\"p=0+%2B-+1\"
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\n" ); document.write( "\"x=1\"
\n" ); document.write( "\"f%281%29=1%2B3%2B3%2B1=8\"
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\n" ); document.write( "\"x=-1\"
\n" ); document.write( "\"f%28-1%29=-1%2B3-3%2B1=0\"
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\n" ); document.write( "So \"x=-1\" is a root and \"x%2B1\" is a factor of the polynomial.
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\n" ); document.write( "Now use polynomial long division to find the remaining quadratic,
\n" ); document.write( "First term: \"highlight%28+x%5E2%29\"
\n" ); document.write( "\"x%5E2%28x%2B1%29=x%5E3%2Bx%5E2\"
\n" ); document.write( "Subtract that product from the original polynomial to get the remainder,
\n" ); document.write( "\"%28x%5E3%2B3x%5E2%2B3x%2B1%29-%28x%5E3%2Bx%5E2%29=2x%5E2%2B3x%2B1\"
\n" ); document.write( "Second term:\"highlight%282x%29\"
\n" ); document.write( "\"2x%28x%2B1%29=2x%5E2%2B2x\"
\n" ); document.write( "Subtract that product from the previous remainder to get the new remainder,
\n" ); document.write( "\"%282x%5E2%2B3x%2B1%29-%282x%5E2%2B2x%29=x%2B1\"
\n" ); document.write( "Final term:\"highlight%281%29\"
\n" ); document.write( "\"1%28x%2B1%29=x%2B1\"
\n" ); document.write( "Subtract that product from the previous remainder to get the new remainder,
\n" ); document.write( "\"%28x%2B1%29-%28x%2B1%29=0\"
\n" ); document.write( "Gather all of the terms.
\n" ); document.write( "\"%28x%5E3%2B3x%5E2%2B3x%2B1%29%2F%28x%2B1%29=x%5E2%2B2x%2B1=%28x%2B1%29%5E2\"
\n" ); document.write( "\"x%5E3%2B3x%5E2%2B3x%2B1=%28x%2B1%29%5E3\"
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\n" ); document.write( "A triple root at \"x=-1\"
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