document.write( "Question 320658: How many liters of a 45% acid solution must be added to 15 liters of a 30% acid solution to produce a 35% acid solution?\r
\n" ); document.write( "\n" ); document.write( " I tried 45%(x) + 30%*(15-x)= (35%)(15)
\n" ); document.write( ".45+.30(15-x)=(.35)(15)
\n" ); document.write( ".45x + 4.5 -.30x+ 5.25
\n" ); document.write( ".15x +4.5 = 5.25
\n" ); document.write( " -4.5 = -4.5\r
\n" ); document.write( "\n" ); document.write( ".75/.15 = 5% answer\r
\n" ); document.write( "\n" ); document.write( "Thank you; Word problems are definitely my weakness in understanding and setting up. \r
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Algebra.Com's Answer #229683 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
How many liters of a 45% acid solution must be added to 15 liters of a 30% acid solution to produce a 35% acid solution?
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\n" ); document.write( "I'm not sure what you are doing here, but let's think this out.
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\n" ); document.write( "Let x = amt of 45% solution to be added
\n" ); document.write( "then we know the resulting mixture will be (x+15), right?
\n" ); document.write( "Use the decimal equiv, write a typical mixture equation
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\n" ); document.write( ".45x + .30(15) = .35(x+15)
\n" ); document.write( ":
\n" ); document.write( ".45x + 4.5 = .35x + 5.25
\n" ); document.write( ":
\n" ); document.write( ".45x - .35x = 5.25 - 4.5
\n" ); document.write( ":
\n" ); document.write( ".10x = .75
\n" ); document.write( "x = \".75%2F.1\"
\n" ); document.write( "x = 7.5 liters to be added
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\n" ); document.write( "Check this in the original equation
\n" ); document.write( ".45(7.5) + .30(15) = .35(7.5+15)
\n" ); document.write( "3.375 + 4.5 = .35(22.5)
\n" ); document.write( "7.875 = 7.875; confirms our solution
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\n" ); document.write( "did this make sense to you?
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