document.write( "Question 320726: The area of the rectangle is 100 square cm. If a square built using a diagonal of this rectangle as one of its sides, the square has area 700 square cm. What is the perimeter of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #229669 by mananth(16946)![]() ![]() You can put this solution on YOUR website! The area of the rectangle is 100 square cm. If a square built using a diagonal of this rectangle as one of its sides, the square has area 700 square cm. What is the perimeter of the rectangle?\r \n" ); document.write( "\n" ); document.write( "let length be x \n" ); document.write( "width be y \n" ); document.write( "xy=100 \n" ); document.write( ".. \n" ); document.write( "the diagonal of the rectangle = sqrt(x^2+y^2) \n" ); document.write( "this is the side of the square \n" ); document.write( "Area of this square = sqrt(x^2+y^2)*sqrt(x^2+y^2) \n" ); document.write( "= x^2+y^2 \n" ); document.write( ".. \n" ); document.write( "x^2+y^2=700 \n" ); document.write( "x^2+2xY+y^2= 700+2xy \n" ); document.write( "(x+y)^2= 700+200 \n" ); document.write( "(x+y)^2= 900 \n" ); document.write( "(x+y)= 30 \n" ); document.write( "(x+100/x)=30 \n" ); document.write( "x^2+100 /x =30 \n" ); document.write( "x^2+100=30x \n" ); document.write( "x^2-30x+100=0 \n" ); document.write( "The roots of the equation x1 , x2 \n" ); document.write( "x1= 30 +sqrt(900-400) /2 \n" ); document.write( "x1=26.18 cm \n" ); document.write( "x2= 30 -sqrt(900-400) /2 \n" ); document.write( "x2=3.82 cm \n" ); document.write( ".. \n" ); document.write( "perimeter of rectangle = (2*3.82)+(2*25.18) \n" ); document.write( "=60 cm \n" ); document.write( " |