document.write( "Question 320673: A single die is rolled twice. Find the probability of rolling an odd number the first time and a number greater than 3 the second time.\r
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Algebra.Com's Answer #229664 by Fombitz(32388)\"\" \"About 
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P(odd)=3/6=1/2 (1,3,5)
\n" ); document.write( "P(>3)=3/6=1/2 (4,5,6)
\n" ); document.write( "The events are independent, multiply the probabilities.
\n" ); document.write( "P(odd then >3)=(1/2)(1/2)=1/4
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