document.write( "Question 320604: You invest $8000 in two accounts paying 8% and 5% respectively. If the interest at year's end is 490, how much of that amount did you invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #229629 by mananth(16946)\"\" \"About 
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$8000 in two accounts paying 8% and 5%
\n" ); document.write( "Total interest = $490
\n" ); document.write( "..
\n" ); document.write( "let $ x be invested at 8%
\n" ); document.write( "8000-x will be invested at 5%
\n" ); document.write( "..
\n" ); document.write( "0.08x+0.05(8000-x)=490
\n" ); document.write( "0.08x+400-0.05x=490
\n" ); document.write( "0.03x=90
\n" ); document.write( "x=3000
\n" ); document.write( "$ 3000 at 8%
\n" ); document.write( "$5000 at 5 %
\n" ); document.write( "CHECK
\n" ); document.write( "0.08*3000+0.05*5000 = 490
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