document.write( "Question 320619: Two negative intergers have the sum of -13 and a product of 42. What are the interges? \n" ); document.write( "
Algebra.Com's Answer #229615 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I don't know what intergers or interges are. If you have two negative integers that have the sum of -13 and a product of 42, then I can show you how to determine the value of the two integers. In the first place, you should be able to quickly see that the answer is -6 and -7, just because you are that intimately familiar with the 12 by 12 multiplication tables. (if that is not true, go back and study your multiplication facts until it is true and you exude products of integers from 1 to 12 from your pores).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let represent one of the integers. Let represent the other one.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Which is to say:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Then\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Substituting:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Putting it into standard form:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now all you need to do is factor and solve. The two roots will be the two integers you seek.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );