document.write( "Question 320359: At first two different pipes running together will fill a tank in 20/3 minutes. The rate that water runs through each of the pipes is then adjusted. If one pipe, running alone, takes 1 minute less to fill the tank at its new rate, and the other pipe, running alone, takes 2 minutes more to fill the tank at its new rate, then the two running together will fill the tank in 7 minutes. Find in what time the tank will be filled by each pipe running alone at the new rates. \n" ); document.write( "
Algebra.Com's Answer #229563 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! At first two different pipes running together will fill a tank in 20/3 minutes. \n" ); document.write( " The rate that water runs through each of the pipes is then adjusted. \n" ); document.write( " If one pipe, running alone, takes 1 minute less to fill the tank at its new \n" ); document.write( "rate, \n" ); document.write( " and the other pipe, running alone, takes 2 minutes more to fill the tank \n" ); document.write( " at its new rate, \n" ); document.write( " then the two running together will fill the tank in 7 minutes. \n" ); document.write( ": \n" ); document.write( " Find in what time the tank will be filled by each pipe running alone at the new rates. \n" ); document.write( ": \n" ); document.write( "let a = first pipe original time alone (in minutes) \n" ); document.write( "let b = second pipe original time alone \n" ); document.write( "then \n" ); document.write( "(a-1) = first pipe adjusted rate time alone \n" ); document.write( "(b+2) = 2nd pipe adjusted rate time alone \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "Original, working together equation \n" ); document.write( " \n" ); document.write( "We convert this to \n" ); document.write( " \n" ); document.write( "multiply by 3ab, results \n" ); document.write( "20b + 20a = 3ab \n" ); document.write( "20b - 3ab = -20a \n" ); document.write( "b(20-3a) = -20a \n" ); document.write( "b = \n" ); document.write( ": \n" ); document.write( "Adjusted, working together equation \n" ); document.write( " \n" ); document.write( "multiply by (a-1)(b+2), results \n" ); document.write( "7(b+2) + 7(a-1) = (a-1)(b+2) \n" ); document.write( "7b + 14 + 7a - 7 = ab + 2a - b - 2 \n" ); document.write( "Combine \n" ); document.write( "7b + b + 7a - 2a + 14 - 7 + 2 = ab \n" ); document.write( "8b + 5a + 9 = ab \n" ); document.write( "Multiply by 3, \n" ); document.write( "24b + 15a + 27 = 3ab \n" ); document.write( "The two equations = 3ab, therefore \n" ); document.write( "24b + 15a + 27 = 20b + 20a \n" ); document.write( "24b - 20b + 15a - 20a = -27 \n" ); document.write( "4b - 5a = -27 \n" ); document.write( "replace b with \n" ); document.write( "4( \n" ); document.write( " \n" ); document.write( "Get rid of all those negatives, multiply by -1 \n" ); document.write( " \n" ); document.write( "Multiply by (20-3a), results \n" ); document.write( "80a + 5a(20-3a) = 27(20-3a) \n" ); document.write( "80a + 100a - 15a^2 = 540 - 81a \n" ); document.write( "180a - 15a^2 = 540 - 81a \n" ); document.write( "Combine on the right \n" ); document.write( "0 = 15a^2 - 81a - 180a + 540 \n" ); document.write( "A quadratic equation \n" ); document.write( "15a^2 - 261a + 540 = 0 \n" ); document.write( "Simplify, divide by 3 \n" ); document.write( "5a^2 - 87a + 180 = 0 \n" ); document.write( "Factor this \n" ); document.write( "(5a-12)(a-15) = 0 \n" ); document.write( "Reasonable solution here \n" ); document.write( "a = 15 hrs pipe a originally \n" ); document.write( "then \n" ); document.write( "15 - 1 = 14 hrs pipe a alone at the new rate \n" ); document.write( ": \n" ); document.write( "Find b original value \n" ); document.write( "b = \n" ); document.write( "b = \n" ); document.write( "b = \n" ); document.write( "b = \n" ); document.write( "b = +12 hrs pipe b originally \n" ); document.write( "then \n" ); document.write( "12 + 2 = 14 hrs pipe b alone at the new rate \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the adjusted equation \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Seems like there should be an easier way to do this, but I see no one else has \n" ); document.write( "worked this problem in 12 hrs, so here it is.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |