document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=320471>Question 320471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I decide to take up alpaca farming. I will build an alpaca pen next to my house. (Since it is next to my house, I don't need any fencing on the side where my house is. My house is huge, so I dont have to worry about that side being too short.) I have 800 feet of fencing. I am going to make a rectangular fence.\r<BR>\n" );
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document.write( "a. if I want the pen to have an area of 15,200 sq feet, what should the dimensions be?<BR>\n" );
document.write( "b. I want to give my alpacas as much room as possible. What is the most area I can have in this rectangular pen, using my 800 feet of fencing? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229562 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229562\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> YOUR RECTANGLAR AREA WILL HAVE 2 EQUAL SIDES & 1 LENGTH.<BR>\n" );
document.write( "P=2W+L<BR>\n" );
document.write( "800=2W+L<BR>\n" );
document.write( "L=800-2W<BR>\n" );
document.write( "A=LW<BR>\n" );
document.write( "15,200=(800-2W)W<BR>\n" );
document.write( "15,200=800W-2W^2<BR>\n" );
document.write( "2W^2-800W+15,200=0<BR>\n" );
document.write( "2(W^2-400W+7,600)=0<BR>\n" );
document.write( "2(W-380)(W-20)=0<BR>\n" );
document.write( "W-380=0<BR>\n" );
document.write( "W=380 FT. <BR>\n" );
document.write( "L=800-2*380=800-760=40 FT.<BR>\n" );
document.write( "OR:<BR>\n" );
document.write( "W-20=0<BR>\n" );
document.write( "W=20 FT.<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "L=800-2W<BR>\n" );
document.write( "AREA=LW<BR>\n" );
document.write( "(800-2W)*W<BR>\n" );
document.write( "800W-2W^2<BR>\n" );
document.write( "-2W^2+800W<BR>\n" );
document.write( "-2(W^2-400W) NOW COMPLETE THE SQUARE.<BR>\n" );
document.write( "(400/2)^2=200^2=40,000<BR>\n" );
document.write( "-2(W^2-400W+40,000)=40,000<BR>\n" );
document.write( "-2(W-200)^2=40,000<BR>\n" );
document.write( "W-200=0<BR>\n" );
document.write( "W=200 ANS. FOR EACH OF THE SHORT WIDTHS.<BR>\n" );
document.write( "L=800-2*200<BR>\n" );
document.write( "L=800-400=400 ANS. FOR THE LENGTH,<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "A=400*200=80,000 FT^2 IS THE MAX. AREA.<BR>\n" );
document.write( "TEST:<BR>\n" );
document.write( "USE 199 & 402 FT.<BR>\n" );
document.write( "AREA=199*402=79,998 FT^2<BR>\n" );
document.write( "TEST 201 & 398<BR>\n" );
document.write( "AREA=201*398=79,998 FT^2 <BR>\n" );
document.write( " </SPAN>\n" );
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