document.write( "Question 320495: Hot Shot Battery manufactures batteries in batches of 15 with a defective rate of 10%
\n" ); document.write( "a.What is the probability that exactly 2 will be defective?\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "b.What is the probability that between 2 and 4 inclusive will be defective?\r
\n" ); document.write( "\n" ); document.write( "c.What is the probability that no batteries will be defective? 0
\n" ); document.write( "
\n" ); document.write( "d.Find the mean 
\n" ); document.write( "
\n" ); document.write( "e.Find the variance 2
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #229513 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Hot Shot Battery manufactures batteries in batches of 15 with a defective rate of 10%
\n" ); document.write( "---
\n" ); document.write( "Binomial Problem with n= 15 and p = 0.10
\n" ); document.write( "-----------------------------------------------
\n" ); document.write( "a.What is the probability that exactly 2 will be defective?
\n" ); document.write( "P(x+2) = 15C2*0.10^2*0.90^13 = binompdf(15,0.1,2) = 0.2669
\n" ); document.write( "------------------------------------- \r
\n" ); document.write( "\n" ); document.write( "b.What is the probability that between 2 and 4 inclusive will be defective?
\n" ); document.write( "binomcdf(15,0.1,4)-binomcdf(15,0.1,1) = 0.4382
\n" ); document.write( "------------------------------------
\n" ); document.write( "c.What is the probability that no batteries will be defective?
\n" ); document.write( "P(x=0) = 15C0*0.1^0*0.9^15 = 0.9^15 = 0.2059
\n" ); document.write( "------------------------------------
\n" ); document.write( "d.Find the mean ;
\n" ); document.write( "mean of a binomial distribution = np
\n" ); document.write( "np = 15*0.1 = 1.5
\n" ); document.write( "------------------------------------
\n" ); document.write( "e.Find the variance
\n" ); document.write( "variance = npq
\n" ); document.write( "npq = 1.5*0.9 = 1.35\r
\n" ); document.write( "\n" ); document.write( "=====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );