document.write( "Question 320446: If ABCDEF is a regular hexagon, how to calculate
Algebra.Com's Answer #229493 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! If ABCDEF is a regular hexagon, how to calculate \n" ); document.write( "\n" ); document.write( "the vertex of angle ACD is point C, rays CA and CD have a common endpoint at C, \n" ); document.write( "now I think figuring out angle ACD depends on how you are labeling the vertices of the regular hexagon, \n" ); document.write( "the interior angle of a regular polygon is (180(n-2))/n where n is number of sides, \n" ); document.write( "3 sides --> (180(3-2))/3 = 180/3 = 60 \n" ); document.write( "4 sides --> (180(4-2))/4 = 360/4 = 90 \n" ); document.write( "5 sides --> (180(5-2))/5 = (180*3)/5 = 540/5 = 108 \n" ); document.write( "6 sides --> (180(6-2))/6 = 720/6 = 120, \n" ); document.write( "I am labeling the vertices from top left and going clockwise ABCDEF, \n" ); document.write( "angles ABC, BCD, CDE, DEF, EFA, and FAB are all 120 degrees, \n" ); document.write( "in triangle ABC the angles should be 120-30-30, so angle ACB is 30 degrees, \n" ); document.write( "then angle ACD = angle BCD - angle ACB = 108 - 30 = 78 degrees \n" ); document.write( "---- \n" ); document.write( "OKAY was informed that angle ACD should be 90 degrees and not 78 degrees. \n" ); document.write( "Reading through my answer I gave now, oh dear I see what I did wrong... \n" ); document.write( "Angle BCD is 120 degrees not 108 degrees. \n" ); document.write( "And angle ACB is still 30 degrees. \n" ); document.write( "So 120 - 30 = 90, and angle ACD is 90 degrees. \n" ); document.write( "I apologize for any inconvenience I may have caused.\r \n" ); document.write( "\n" ); document.write( " |