document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=320333>Question 320333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle DSR ,if 3times angle D=4times angle S=6times angle R.Calculate the measures of angles D,S,R </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #229485 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=229485\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> R+S+D=180<BR>\n" );
document.write( "3D=4S=6R<BR>\n" );
document.write( "4S=3D<BR>\n" );
document.write( "S=3D/4<BR>\n" );
document.write( "6R=3D<BR>\n" );
document.write( "R=3D/6<BR>\n" );
document.write( "R=D/2<BR>\n" );
document.write( "D/2+3D/4+D=180<BR>\n" );
document.write( "(2D+3D+4D)/4=180<BR>\n" );
document.write( "9D/4=180<BR>\n" );
document.write( "9D=4*180<BR>\n" );
document.write( "9D=720<BR>\n" );
document.write( "D=720/9<BR>\n" );
document.write( "D=80 ANS. FOR ANGLE D.<BR>\n" );
document.write( "S=3*80/4=240/4=60 ANS FOR ANGLE S.<BR>\n" );
document.write( "R=80/2=40 ANS.  FOR ANGLE R.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "80+60+40=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );