document.write( "Question 320390: Find where two parabolas y= -2(x-3)^2 + 4 and y=2(x-2)^2 -1 intersect each other.\r
\n" ); document.write( "\n" ); document.write( "I keep coming up with another quadratic equation instead of a point! I also tried sketching both parabolas, but the exact point of intersection is difficult to verify.
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Algebra.Com's Answer #229442 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
You're getting a quadratic equation because they intersect at two points.
\n" ); document.write( "If they only intersected at one point, you would get a linear equation.
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\n" ); document.write( " \"-2%28x-3%29%5E2%2B4=2%28x-2%29%5E2+-1\"
\n" ); document.write( "\"-2%28x%5E2-6x%2B9%29%2B4=2%28x%5E2-4x%2B4%29-1\"
\n" ); document.write( "\"-2x%5E2%2B12x-18%2B4=2x%5E2-8x%2B8-1\"
\n" ); document.write( "\"4x%5E2-20x%2B21=0\"
\n" ); document.write( "Factor
\n" ); document.write( "\"%282x-7%29%282x-3%29=0\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"2x-7=0\"
\n" ); document.write( "\"2x=7\"
\n" ); document.write( "\"x=7%2F2\"
\n" ); document.write( "Then use either equation to find y.
\n" ); document.write( "\"y=2%287%2F2-4%2F2%29%5E2-1\"
\n" ); document.write( "\"y=2%283%2F2%29%5E2-1\"
\n" ); document.write( "\"y=9%2F2-2%2F2\"
\n" ); document.write( "\"y=7%2F2\"
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\n" ); document.write( "\"2x-3=0\"
\n" ); document.write( "\"2x=3\"
\n" ); document.write( "\"x=3%2F2\"
\n" ); document.write( "Again, find y,
\n" ); document.write( "\"y=2%283%2F2-4%2F2%29%5E2-1\"
\n" ); document.write( "\"y=2%28-1%2F2%29%5E2-1\"
\n" ); document.write( "\"y=-1%2F2-2%2F2\"
\n" ); document.write( "\"y=-1%2F2\"
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\n" ); document.write( "(7/2,7/2) and (3/2,-1/2)
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